CDO

Hi Nurul,

I would guess that you can create a kind of a mask for each timestep where values in your given range will be 1 and all others 0, and pipe the result to timsum.

For values between -4 and -1:

cdo -timsum -setrtoc2,-4,-1,1,0 infile outfile

-Karin

Another way, e.g for variable pr:

cdo -timsum -expr,'pr=((pr>=-4.0) && (pr<=-1.0)) ? 1.0 : 0.0' infile outfile

ya, and then after i change all value in range needed as 1, can i calculate how many 1 were there? and divide by 420

Have you tried the examples above with your data? Did you have a look at the result with ' cdo info outfile '?

Ok, let's start with the explanation. First, you have to know that you need to read the operator list from right to left! The output of each operator is internally piped to the next operator.

1. Set all values between -4 and -1 to value 1 and all other values outside the range to 0

-expr,'pr=((pr>=-4.0) && (pr<=-1.0)) ? 1.0 : 0.0'

2. ' Add of the 1s ' - means to compute the sum of the values for each grid cell for all time steps

-timsum

3. To divide the values by a constant 420

-divc,420

CDO command line at the end:

cdo -divc,420 -timsum -expr,'pr=((pr>=-4.0) && (pr<=-1.0)) ? 1.0 : 0.0' infile outfile

It is always a good starting point to read the FAQ and the User guide.

thank you! Ive tried but I also currently trying to prevent from NaN is changing to 0 too.