Convert time steps to vertical levels
Added by Noam Chomsky over 4 years ago
Because of some constraint in R when creating the netCDF file, my file has 10 time step instead of 10 vertical levels. Is it possible to convert the time steps into vertical levels? I also do not need to have the time component so what am looking for is a three dimension file.
Here are the details
File format : NetCDF
-1 : Institut Source T Steptype Levels Num Points Num Dtype : Parameter ID
1 : unknown unknown v instant 1 1 16200 1 F32 : -1
Grid coordinates :
1 : projection : points=16200 (180x90)
mapping : undefined
longitude : -179 to 179 by 2 degrees_east
latitude : 89 to -89 by -2 degrees_north
Vertical coordinates :
1 : surface : levels=1
Time coordinate : 10 steps
YYYY-MM-DD hh:mm:ss YYYY-MM-DD hh:mm:ss YYYY-MM-DD hh:mm:ss YYYY-MM-DD hh:mm:ss
0000-00-00 00:00:00 0000-00-00 00:00:00 0000-00-00 00:00:00 0000-00-00 00:00:00
0000-00-00 00:00:00 0000-00-00 00:00:00 0000-00-00 00:00:00 0000-00-00 00:00:00
0000-00-00 00:00:00 0000-00-00 00:00:00
I would like to get
File format : NetCDF
-1 : Institut Source T Steptype Levels Num Points Num Dtype : Parameter ID
1 : unknown unknown c instant 10 1 16200 1 F32 : -1
Grid coordinates :
1 : lonlat : points=16200 (180x90)
longitude : -179 to 179 by 2 degrees_east circular
latitude : 89 to -89 by -2 degrees_north
Vertical coordinates :
1 : generic : levels=10
sfc : 1 to 10 by 1
Thanks
Replies (4)
RE: Convert time steps to vertical levels - Added by Ralf Mueller over 4 years ago
hi Noam!
I think a renaming of variable/dimension from time
to level
should do it. NCOs ncrename
is the right tool for it, I guess. In case you upload the file, I possibly can say more.
cheers
ralf
RE: Convert time steps to vertical levels - Added by Noam Chomsky over 4 years ago
Thanks Ralf, it's easier for me to post the ncdump. I have tried ncrename but I can't figure out what the name of the time is, it seems "z"
dimensions: longitude = 180 ; latitude = 90 ; z = UNLIMITED ; // (10 currently) variables: int crs ; crs:proj4 = "+proj=longlat +datum=WGS84 +ellps=WGS84 +towgs84=0,0,0" ; double longitude(longitude) ; longitude:units = "degrees_east" ; longitude:long_name = "longitude" ; double latitude(latitude) ; latitude:units = "degrees_north" ; latitude:long_name = "latitude" ; int z(z) ; z:units = "unknown" ; z:long_name = "z" ; float wbm(z, latitude, longitude) ; wbm:units = "kg" ; wbm:_FillValue = -3.4e+38f ; wbm:grid_mapping = "crs" ; wbm:proj4 = "+proj=longlat +datum=WGS84 +ellps=WGS84 +towgs84=0,0,0" ; wbm:min = 14., 11., 10., 10., 8., 1., 11., 1., 1., 6. ; wbm:max = 1600., 2800., 1991., 1282., 620., 46., 38., 80., 24.5, 13. ;
RE: Convert time steps to vertical levels - Added by Noam Chomsky over 4 years ago
It seems the dimension time is not present.
RE: Convert time steps to vertical levels - Added by Ralf Mueller over 4 years ago
try to rename 'z' to 'time' (dim and var) and check with CDO again - that is my best guess